Math, asked by Shareq, 10 months ago

Find the value of k for quadratic equation k x square (2k+4) x+9=0, so that they have two equal roots.​

Answers

Answered by revathijaya18
2

Answer:

k=4,1

Step-by-step explanation:

kx2+(2k+4)x+9=0

d=b2-4ac

=(2k+4)2-4k(9)

=4k2+16+16k-36k

4k2-20k+16=0

By factorisation method

4k2-16k-4k+16=0

4k(k-4)-4(k-4)

(4k-4)(k-4)

4k=4. k=0+4

k=1. k=4

k=4,1

Answered by nagaramhemalatha99
0

Answer:

Step-by-step explanation:

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