Find the value of k for quadratic equation k x square (2k+4) x+9=0, so that they have two equal roots.
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Answered by
2
Answer:
k=4,1
Step-by-step explanation:
kx2+(2k+4)x+9=0
d=b2-4ac
=(2k+4)2-4k(9)
=4k2+16+16k-36k
4k2-20k+16=0
By factorisation method
4k2-16k-4k+16=0
4k(k-4)-4(k-4)
(4k-4)(k-4)
4k=4. k=0+4
k=1. k=4
k=4,1
Answered by
0
Answer:
Step-by-step explanation:
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