Question

find the value of K for quadratic equation kxsquare+(2x+4)x+9=0​

Answer 1

Answer:

Hey mate here is ur answer↓

Step-by-step explanation:

Equation:-

kx²+(2k+4)x+9=0

a=k,b=(2k+4),c=9

d=b²-4ac

=>(2k+4)²-4×k×9=0 [°•°Roots are real,equal d=0]

4k²+16k+16-36k=0

4k²-20k=-16

4k(k-5)=-16

k(k-5)=-16/4=-4

=>k=-4

k-5=0

=>k=5

Hope it helps™✓