find the value of k for the equation( 2 k - 1 )x^2 - 2( k + 1 )x - 1 = 0 has equal and real roots
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Answer:
b^2-4ac=0
(-2k-2)^2-4(2k-1)(-1)=0
(-4k^2-8k-4)-4(-2k+1)=0
-4k^2-8k-4+8k-4=0
-4k^2-8=0
-4(k^2+2)=0
k^2+2=0
k^2= -2
k= -√2 _Answer
Step-by-step explanation:
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