Question

Find the value of k for the equation 2 x square + kx + 3 is equal to zero where is equal has real and equal roots

Answer 1

Answer:

Given Equation: 2x² + kx + 3

It is said that the above equation has real and equal roots.

Therefore we can say that the value of the discriminant is equal to 0.

⇒ b² - 4ac = 0

According to the question, a = 2, b = k, c = 3

Therefore on substituting we get,

⇒ k² - 4 ( 2 ) ( 3 ) = 0

⇒ k² - 24 = 0

⇒ k² = 24

⇒ k = √24 = ± 2√6

Therefore the value of k is ± 2√6.

Hope it helped !!

Answer 2

Solutions:

k² - 4(2)(3) = 0

k² - 24 = 0

k² = 24

k = √24

k = 2√6.

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