Question

Find the value of 'k'for the equation"2x^2+kx+3=0.So that they two have equal roots​

Answer 1

Step-by-step explanation:

given,

2x^2+Kx+3

here it is in the form ax^2+bc+C=0

here a=2, b=K, c=3

if it has two equal roots. then ∆=0

b^2-4ac=0

k^2-4(2)(3)=0

k^2-24=0

k^2=24

k=√24

k=2√6

Answer 2

to have equal roots the condition is b^2-4ac=0.

here a=2 b= k c= 3

so,k^2-4(2)(3)=0

k^2-24=0

k^2=24

k=√24

We split it into the following:

=√4⋅6

Now, we use the radical rule which states that, √ab=√a⋅√b,a,b>0.

So, we get,

=√4⋅√6

=2√6.