find the value of k for the equation 2x²+kx+3=0 has equal roots?
Answers
Answered by
7
Answer:
k = +24 or -24
Step-by-step explanation:
The equation is 2x²+kx+3=0
a = 2, b = k and c = 3
Since the equation has equal roots,
b² - 4ac = 0
(k)² - 4(2)(3) = 0
k² - 24 = 0
k² = 24
k = +24 or -24
Answered by
4
Answer:
the following equation is
2x² + kx + 3 = 0
it is given that it has real roots...
=> discriminant = 0
=> b² - 4ac = 0
=> k² - 4 × 2 × 3 = 0
=> k = +- root of 24
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