Question

Find the value of 'k'for the equation "kx^2+2(k-4)x+2=0.So that they have two equal roots.​

Answer 1

Heyaa☺

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Given,

Equation =》 Kx^2 + 2k-8x + 2 = 0

The roots are equal.

=》 b^2 - 4ac = 0

=》 (2k - 8)^2 - 4(k)(2) = 0

=》 (2k)^2 + (-8)^2 - 2(2k)(-8) - 8k = 0

=》 4k^2 + 64 - 32k - 8k = 0

=》 4k^2 + 64 - 14k = 0.

Product of roots =》 -c / a

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Hope you understand..✌

Answer 2

Answer:

We know that, when the equation has two equal and real roots, the discriminant : b^2 - 4ac = 0

Here, we have :

a = k

b = 2k - 8

c = 2

Put in the formula and solve. We get the final value as :

ӄ = 8, 2