Find the value of k for the equetion
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Answered by
6
Answer:
p(y) = ky2 + 2y - 3k
Compare p(y) with standard form ax2 + bx + c
a = k, b = 2, c = -3k
According to question,
Sum of zeroes = 2(Product of zeroes)
- ⇒−ba=2×ca
- ⇒−2k=2×−3kk
- ⇒2k=6
- ⇒k=13
Answered by
0
Step-by-step explanation:
I think the value of k is 13
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