Math, asked by sanjay9259, 1 month ago

Find the value of k for the equetion
2 {x}^{2}  + kx + 3 = 0

Answers

Answered by ANSHUKUMAR3456
6

Answer:

p(y) = ky2 + 2y - 3k

Compare p(y) with standard form ax2 + bx + c

a = k, b = 2, c = -3k

According to question,

Sum of zeroes = 2(Product of zeroes)

  • ⇒−ba=2×ca
  • ⇒−2k=2×−3kk
  • ⇒2k=6
  • ⇒k=13
Answered by ittheretimetotime
0

Step-by-step explanation:

I think the value of k is 13

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