Question

Find the value of k for the following linear equation where x=14 and y=3.(i)kx-3y+7=0​

Answer 1

Answer:

kx-3y+7=0

14k-3×3+7=0

14k-9+7=0

14k-2=0

14k=2

k=1/7

Answer 2

Hope this helps you ;)

$x = 14 \: \: \: \: \: \: y = 3$

$kx - 3y + 7 = 0$

$k(14) - 3(3) + 7 = 0$

$14k - 9 + 7 = 0$

$14k = 2$

$k = \frac{2}{14}$

$k = \frac{1}{7}$