Question

Find the value of k for the following pair of linear equations have infinity solutions :kx^2-3x-6=0 and 3x^2+kx+6=0

Answer 1

Answer:

k = 3/2

this is the value of k

Answer 2

Answer:

Here is your answer

In these equations ,

a = k , b = 3 , c = (2k+1)

A = 2(k+1) , B = 9 , C = (7k+1)

These equations has infinity solutions . so ,

a/A = b/B = c/C

k/2k+2 = 3/9 = 2k+1/7k+1

(1) k/2k+2 =3/9

9k = 6k +6

3k = 6

k = 2

So , the value of k is 2

Hope it was helpful

please give me a thanks❤