Question

Find the value of k for the following pair of linear equations have infinity solutions ;

2x+3y=7 ; (k-1)+(k+2)y=3k​

Answer 1

case1) 2x+3(3k)=7
2x+9k=7
2x+9(1)=7
2x+9=7
2x=7-9
2x=-2
X= -2/2
X=-1


case2). . 2x+3(3k)=7
2x+9k=7
2x+9(-2)=7
2x+(-18)=7
2x-18=7
2x=7+18
2X=25
X= 25/2
X=12.5

Answer 2

Solution:
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pls refer to the above attachment
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#PLS FORGIVE MY MESSY HANDWRITING⚪⚫⚪⚫⚪

For infinitely many solutions,
$\frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2}$
So, we plug in the values and eqate them with one another.....
Then cross multipy the values to get an equation..
solving the both the equations simultaneously will give you the answer,
i.e.
k=7
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