Question

find the value of k for the following quadratic eqaution 2x^2 + kx+3 so that they have equal root

Answer 1

2x²+kx+3

For equal
D=0
b²-4ac=0 .

a=2
b=k
c=3

k²-4(2)(3)=0
k²-24=0
k²=24
k=√24
k=2√6

Answer 2

Ans

a=2

b=k

c=3

b^2-4ac=0(having equal roots)

k^2-4*2*3

k^2=24

k=✓24

k=2✓6