Question

Find the value of k for the following quadratic equation, so that it should have equal roots:kx²+ 6x + 1 = 0 *​

Answer 1

Answer:

9

Step-by-step explanation:

We know that,

D=b^2-4ac

=> 0 = 6^2-4×1×k

=> 0=36-4k

=> 4k=36

=> 9

Answer 2

Answer:

k=9

Step-by-step explanation:

Discriminate(D)=$b^{2}-4ac$

For equal roots, D=0

Comparing $b^{2}-4ac$ with $kx^{2} +6x+1$,

b=6, a=k, c=1

$b^{2} -4ac=0$

$6^{2}$- 4k X 1=0

36-4k=0

4k=36

k=9