Question

find the value of k for the following quadratic equation so that ot should have equal roots kx2+6x+1 =0​

Answer 1

We know that,

To have equal roots, the determinant should be equal to 0

${b}^{2} - 4ac = 0$

${6}^{2} - 4 \times k \times 1 = 0$

$36 - 4k = 0$

$36 = 4k$

$\frac{36}{4} = k$

$k = 9$