find the value of k for the following quadratic equation so that it has two real and equal root 5 x ^2- 2 k x + 20 =0
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Answered by
5
Answer:
Quadratic equation:
5x
2
−2kx+20=0
It is given that the roots of the quadratic equation are real and equal, Then discriminant D=0.
Comparing the given equation with ax
2
+bx+c=0
we have a=5,b=−2k and c=20
Now, D=0
∴b
2
−4ac=0
∴(−2k)
2
−4(5)(20)=0
∴4k
2
−400=0
∴k
2
=100
∴k=±10
Thus, k=10 or −10.
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2
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