Question

Find the value of k for the following
quadratic equation so that it has two
real and equal roots.
5x2-2kx+20=0​

Answer 1

$\huge{\underline{\underline{\boxed{\sf{\purple{Answer}}}}}}$

5x²-2kx + 20 = 0

a = 5

b = -2k

c = 20

Discriminant (d) = b²-4ac

For real and equal roots :

b²-4ac = 0

(-2k)² - 4(5)(20) = 0

4k² - 400 = 0

4k² = 400

k² = 400/4

k² = 100

k = √100

k = 10