Find the value of k for the following quadratic equation so that it has two equal roots kx2 + 2x - 1 = 0
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Answered by
7
Hi user
Here's the answer
For a quadratic equation having equal roots, the discriminant is equal to zero.
Q.E = kx² + 2x - 1
a = k , b = 2 , c = - 1
Discriminant = b² - 4ac = 0
= ( 2 )² - 4 * k * - 1 = 0
= 4 - 4k * -1 = 0
= 4 + 4k = 0
= 4k = - 4
=> k = - 4 / 4 = ( - 1 )
Hence value of k is ( - 1 ).
Hope my answer is correct.
Have a good day :-)
Here's the answer
For a quadratic equation having equal roots, the discriminant is equal to zero.
Q.E = kx² + 2x - 1
a = k , b = 2 , c = - 1
Discriminant = b² - 4ac = 0
= ( 2 )² - 4 * k * - 1 = 0
= 4 - 4k * -1 = 0
= 4 + 4k = 0
= 4k = - 4
=> k = - 4 / 4 = ( - 1 )
Hence value of k is ( - 1 ).
Hope my answer is correct.
Have a good day :-)
Answered by
3
Answer:
-1
Step-by-step explanation:
b² - 4ac = 0
= ( 2 )² - 4 * k * - 1 = 0
= 4 - 4k * -1 = 0
= 4 + 4k = 0
= 4k = - 4
=> k = - 4 / 4 = ( - 1 )
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