Find the value of k for the following quadratic equation so that it has two equal roots k x (x – 2) + 6 = 0
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Hey
Here is your answer,
kx(x-2)+6=0
kx^2-2kx+6=0
b^2-4ac= (-2k)^2 -4xkx6
4k^2-24k=0
4k(k-6)=0
4k=0
k=0
k-6=0
k=6
Hope it helps you!
Here is your answer,
kx(x-2)+6=0
kx^2-2kx+6=0
b^2-4ac= (-2k)^2 -4xkx6
4k^2-24k=0
4k(k-6)=0
4k=0
k=0
k-6=0
k=6
Hope it helps you!
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