Question

find the value of K for the linear equation 4x+6y-1=0 and 2x+Ky-7=0 represnts parallel lines?

Answer 1

well we know that in case of parallel lines ...a1/a2=b1/b2 doesn't equal to c1/c2
so
a1=4 ,b1=6 c1=1 and
a2=2,b2=k,c2=7
on putting values
4/2=6/k doesn't=1/7 so k=12÷4
k=3

Answer 2

$<b>1. 4x+6y-1=0</b>$

Put x = 1

4(1)+6y-1=0

1+6y-1=0

6y-0=0

6y=0+0

6y =0

y=0


$<b>2. 2x+ky-7=0</b>$

Put x = 0 put y = 1

2(0)+k(1)-7=0

0+k-7=0

k-7=0

k=0+7

k=7

$<b>Therefore, the value of k=7</b>$

$<b><font color="palered">Thanks</font></b>$

$<b>With♥️</b>$