Question

find the value of k for the quaclratic equation 2æ2+kæ+3=0 if the roots are real and equal
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Answer 1

Given,

2x^2+Kx+3

here it is in the form ax^2+bc+C=0

here a=2, b=K, c=3

if it has two equal roots. then ∆=0

b^2-4ac=0

k^2-4(2)(3)=0

k^2-24=0

k^2=24

k=√24

k=+2√6 or -2√6

Answer 2

Answer:

Hello !!

Step-by-step explanation:

Given,

>>2x^2+Kx+3

>>here it is in the form ax^2+bc+C=0

>>here a=2, b=K, c=3

>>if it has two equal roots. then ∆=0

>>b^2-4ac=0

>>k^2-4(2)(3)=0

>>k^2-24=0

>>k^2=24

>>k=√24

>>k=+2√6 or -2√6

hope it's help you ✌️✌️