Question

Find the value of 'k' for the Quadratic equation 2x2 + kx + 3 = 0 has real
and equal roots.
​

Answer 1

Answer:

Answer

Given,

2x^2+Kx+3

here it is in the form ax^2+bc+C=0

here a=2, b=K, c=3

if it has two equal roots. then ∆=0

b^2-4ac=0

k^2-4(2)(3)=0

k^2-24=0

k^2=24

k=√24

k=+2√6 or -2√6