Find the value of K for the quadratic equation 4x square + kx+ 4= 0, show that it has equal root
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Answered by
0
b^2 -4ac=0
k^2-4*4*4=0
k^2=64
k=8
k^2-4*4*4=0
k^2=64
k=8
Answered by
1
4x²+kx+4 = 0
For equal roots = b²-4ac = 0
k² - 4*4*4 = 0
k² = 64
k = ±8
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