Question

find the value of K for the quadratic equation ' kx(x-2)+6=0, so that they have two equal roots...option are (a) 0 (b) 6 (c) both​

Answer 1

Answer:

see the attachment for answer

Step-by-step explanation:

so your final answer is-

Option B) is correct.

I hope you get your answer

thnx for asking

plzzz mark as brainlist..

Answer 2

Answer:

C) Both

Step-by-step explanation:

kx (x-2) + 6 = 0

=> kx^2 - 2kx + 6 = 0

As, for equal roots, d = 0

=> b^2-4ac = 0

=> 4k^2-24k = 0

=> k^2-6k = 0

=> k(k-6) = 0

So, k=0 or k=6.