Question

find the value of k for the system of pair of linear equation have many solutions 2x+y=7 and 4x+ky=14​

Answer 1

Answer:

The four solutions of the equation 2x + y = 7 are (0, 7), (1, 5), (2, 3) and (-1, 9). (0, 9) is the solution. (1, 9-π) is the solution. (2, 9-2π) is the solution.

Answer 2

Answer:

❃Let:-

$\mathtt{a1 = 2 \: \: \: \: \: \: \: \: b1 = 1 \: \: \: \: \: \: \: \: \: \: c1 = 7}$

$\mathtt{a2 = 4 \: \: \: \: \: \: \: \: b2 = k \: \: \: \: \: \: \: \: \: \: c1 = 14}$

❃Solution:-

For Infinite Many Solution

$\mathtt{ \frac{a1}{a2} = \frac{b1}{b2} = \frac{c1}{c2} }$

$\mathtt{ \frac{2}{4} = \frac{1}{k} = \frac{7}{14} }$

$\mathtt{ \frac{1}{2} = \frac{1}{ k} = \frac{1}{2} }$

$\mathtt{ \frac{1}{2} = \frac{1}{k} }$

Do Cross Multiplication

$\mathtt{k = 2}$

Step-by-step explanation:

I hope this helps you mate.