Question

find the value of k for the trems 2k , k+10 and 3k+2 arein AP​

Answer 1

Answer:

k=6

Step-by-step explanation:

As given 3 terms are in AP,

so with common difference d and first term as 2k, we get

2k+d=k+10

=>d=10-k ....(1)

Also, k+10+d=3k+2

=>k+10+10-k=3k+2 (putting value of from (1))

=>3k+2=20

=>3k=18

=>k=6

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Answer 2

In the above Question , the following information is given -

The terms 2k, k + 10 and 3k + 2 after in AP .

To find -

Find the value of k .

Solution -

If any terms are in AP , the common difference , d is equal in every case .

Here , the terms are 2k , k + 10 and 3k + 2 .

=> d = d

=> ( k + 10 ) - 2k = ( 3k + 2 ) - ( k + 10 )

=> 10 - k = 2k - 8

=> 3k = 18

=> k = 6 .

Thus , the required value of k is 6 .

This is the answer .

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