Question

find the value of k for unique solution kx+2y=4 8x+ky=11
chapter 3 class 10 ​

Answer 1

Step-by-step explanation:

kx+2y=4____(1)

8x+ky=11____(2)

=it has unique solution→a1 / a2 ≠ b1 / b2

=kx+2y-4=0

=8x+ky-11=0

=here;

a1=k, b1=2, c1=(-4)

a2=8, b2=k, c2=(-11)

so,k/8≠2/k

cross multiply k with k and 8 with 2

=k²≠16

=k≠√16

=k≠4

•°•k can be any number other than 4 but k cannot be 4.

hope this helps