Find the value of k for wch 4x+y=7 and 16x+ky=28 have infinitely many solutions
Answers
Answered by
3
Since the equation has infinitely many solutions
A1/a2=b1/b2=c1/c2
Therefore 4/16=1/k=7/28
Therefore 4/16=1/4
Therefore=4
A1/a2=b1/b2=c1/c2
Therefore 4/16=1/k=7/28
Therefore 4/16=1/4
Therefore=4
Answered by
4
4x+y-7=0
16x+ky-28=0
Here a1=4,b1=1,c1=-7
a2=16,b2=k,c2=-28
For Infinite Solutions
a1/a2=b1/b2=c1/c2
4/16=1/k=-7/-28
Now,
4/16=1/k
1/4=1/k
k=4
Again
1/k=-7/-28
1/k=1/4
k=4
16x+ky-28=0
Here a1=4,b1=1,c1=-7
a2=16,b2=k,c2=-28
For Infinite Solutions
a1/a2=b1/b2=c1/c2
4/16=1/k=-7/-28
Now,
4/16=1/k
1/4=1/k
k=4
Again
1/k=-7/-28
1/k=1/4
k=4
Similar questions