find the value of k for wch the quadratic equation 2x^2+5x+k=0 has no reeal rot
Answers
Answered by
0
2x^2+5x+k=0
x(2x+5)+k=0
(2x+5)(k+x)=0
now,
2x+5=0. => x=(-5/2)
then,
x+k= 0. => k= -x = 5/2
x(2x+5)+k=0
(2x+5)(k+x)=0
now,
2x+5=0. => x=(-5/2)
then,
x+k= 0. => k= -x = 5/2
Similar questions