Question

find the value of k for which (1,0) lies on the straight line kx+3y=5

Answer 1

given x coordinate and y coordinate

(1,0)

x=1

y=0

putting value in eqn

kx+3y=5

k(1)+3(0)=5

therefore k=5

Answer 2

Given:- x = 1 and y = 0
Now, kx+3y=5
k(1)+3(0)=5
k+0=5
So, k=5