find the value of k for which (-1,1)lies on the straight line 2x+5y=3k
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1
here is your answer
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1722:
its not ky its 5y
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2
(x,y)=(-1,1)
putting values in eqn gives us
2(-1)+5(1)=3k
-2+5/3=k
3/3=k
therefore k=0
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