Question

Find the value of k for which -1/2is zeros of polynomial x2+2kx-3

Answer 1

Answer:

-11/4

Step-by-step explanation:

k=?, x=-1/2

x2+2kx-3

=(-1/2) 2+2*k*-1/2-3

=1/4-k-3

1/4-3=k

k=1-12/4

k=-11/4

Answer 2

p(x) = x^2 + 2kx - 3

since -1/2 is a zero of p(x) —
p(-1/2) = 0

p(-1/2) = (-1/2)^2 + 2k*(-1/2) - 3 = 0

1/4 - k - 3 = 0

k = 1/4 - 3 = -11/4