Question

find the value of k for which 1 root of quadratic equation is kx^-14x+8=0 is 2

Answer 1

Hi ☺ !!



Here is your answer ✓ ✓✓ ✓



Given that one root of the given quadratic equation is 2.

P(x ) = kx² - 14x + 8 = 0


p (2 ) = k × 2² - 14 × 2 + 8 = 0



=> 4k - 28 + 8 = 0



=> 4k - 20 = 0


=> 4k = 20


=> k = 20/4

=> k = 5



☺ Hope it will help you ☺

$<marquee>$By SaniyaAnwar

$<marquee>$#BeBrainly

Answer 2

$\underline{\large{\textbf{\Hey Mate Here Is Your Answer }}}$

$\underline{\underline{\textbf{Question}}}$

To Find Value Of "K" If 1 Root Of Quadratic Equation

$\mathbf{k{x}^{2}\:-14x + 8}$ Is $\bold{"2 "}$

So Now Let's Move For Solution...

$\underline{\underline{\textbf{Solution...}}}$

So Now Let ..

$\mathbf{P(X) \:= \:k{X}^{2}\: - 14x\:+8 = 0}$

$\textbf{Now According to Question It's Said That 2 Is one Of The Root Of }$

$\textbf{P(X)=0 There For P(2)}$

$\textbf{Should Be Also Equal To 0}$

Therefore..

$\mathbf{P(2) = 0}$

That Is ..

$\mathbf{P(2)\: = \:k\: {(2)}^{2} \:- \:14(2)\: + \:8 \:= \:0 }$

That Is ..

$\mathbf{P(2) \:= \:4k \:-28 \:+ \:8 \:=\: 0}$

That Is Equal To...

$\mathbf{P(2)\: = \:4k \:-20 \:= \:0}$

That Is Now Taking -20 To RHS We Have ...

$\mathbf{P(2) \:= \:4k =\: 20}$

That Is We Have...

$\mathbf{k\:=\:\frac{20}{4}}$

That Is..

$\boxed{\mathbf{k\:=\:5}}$

Hence The Required Answer Is ...

$\boxed{\boxed{\mathbf{k\:=\:5}}}$

$\boxed{\boxed{\bold{THANKS...}}}$