Find the value of k for which (-2,5)(-5,2)& (k,-13) are collinear
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1/2(x1(y2-y3)+x2(y3-y1)+x3(y1-y2)) = 0
= -30+90+5k-2k = 0
= 60+3k = 0
= 3k = -60
= k = -60/3 = -20
= -30+90+5k-2k = 0
= 60+3k = 0
= 3k = -60
= k = -60/3 = -20
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