Question

Find the value of k for which 2K+7,6K-2,8K+4 form three consecutive terms of an AP

Answer 1

Answer: the three terms are in AP,

The condition of the AP is,2b=a+c

2(6k-2)=10k+11

12k-4=10k+11

2k=15

K=15/2

Step-by-step explanation:

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