Question

Find the value of k for which 2k+7,6k-2 and 8k+4 are 3 consecutive numbers of an ap

Answer 1

The answer is given below :

Since the numbers are in AP,

2nd number - 1st number = 3rd number - 1st number

=> (6k - 2) - (2k + 7) = (8k + 4) - (6k - 2)

=> 4k - 9 = 2k + 6

=> 2k = 15

=> k = 15/2

So, the value of k is 15/2.

Thank you for your question.

Answer 2

Answer:

6k-2-2k-7=8k+4-6k+2

4k-9=2k+6

2k=15

k=15/2