Find the value of k, for which 2k+7,6k-2 and 8k+4 are 3 consecutive terms of an ap.
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the value of k=15/2
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Step-by-step explanation:
T2-T1=T2-T3
6K-2-2K+7=6K-2-8K+4
4K+5=2-4K
4K+4K=2-5
8K=-3
K=-3/8
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