Find the Value of k for which 2x²-7kx+24=0 has equal roots.
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q(3)=2*3^2-7*k*3+24=0
=2*9-21k+24=0
=18-21k+24=0
=42-21k=0
=k=42/21
=k=2
=2*9-21k+24=0
=18-21k+24=0
=42-21k=0
=k=42/21
=k=2
raghavsarmukad:
Its a Quadratic Equation, not a polynomial.
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