Question

find the value of k for which 3 X square + 2 X + K equal to zero has real roots​

Answer 1

Answer:1/3

Step-by-step explanation:

For equal root √D is equals to zero.

√D =b^2-4ac

0 = (2)^2-4(3)(k)

0 = 4 - 12k

-4 = -12k

4 = 12k

4/12 = k

1/3 = k

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Answer 2

For the real roots, the value of k is $k\leq\frac{1}{3}$

Step-by-step explanation:

The quadratic equation is

$3x^2+2x+k=0$

Here, we have

a=3, b= 2, c=k

For real roots, we have

$D\geq0\\\\b^2-4ac\geq0\\\\2^2-4(3)(k)\geq0\\\\4-12k\geq0\\\\12k\leq4\\\\k\leq\frac{1}{3}$

Therefore, for the real roots, $k\leq\frac{1}{3}$

#Learn More:

Find the value of k for which the quadratic equation 2x² -kx + k= 0 has equal roots.

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