Question

Find the value of k, for which 4x²-3kx+9=0 has real roots .

Answer 1

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Answer 2

Answer:

The values of k belong to R-(4,4)

Step-by-step explanation:

The given equation is

$4 {x}^{2} - 3kx + 9 = 0$

For the quadratic equation to have real roots,the discriminant of the equation is greater than or equal to zero.Therefore,

[tex]( - 3k) {}^{2} - 4(4)(9) ≥ 0 \\ = > 9 {k}^{2} - 144 ≥ 0 \\ = > {k}^{2} -16≥0 = > (k+4)(k-4)≥0 \\k≤-4 and k≥4

Therefore,the values of k belongs to R-(4,4)

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