Find the value of k for which each of the following equations has equal roots.
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a=3k +1 , b= 2k + 2 and c= k
the equation has real and equal roots
therefore，
b² - 4ac =0
(2k+2)² - 4(3k +1)(k)= 0
4k²+8k+4-12k²-4k = 0
-8k² +4k +4 = 0
-2k² +k +1 = 0
(k+2) (k-1) = 0
k= -2 OR 1
plz mark brainliest
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