Question

find the value of k for which each of the following system of linear equations has an infinite number of solutions
(k-1)x-y=5
(k+1)x+(1-k)y=(3k+1)​

Answer 1

Answer:

k = 3

Step-by-step explanation:

(k-1)/(k+1) = -1/(1-k) = -5/-(3k+1)​

-1/(1-k) = -5/-(3k+1)​

-3k-1 = 5-5k

-3k+5k = 5+1

2k = 6

k = 3

Hope it helps

Thanks !