Find the value of k for which each of the following system of equation have infinatly many solutions
1)kx-2y+6=0
4x-3y+9=0
2)2x-3y=7
(K+2)x-(2k+1)y=3(2k-1)
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Answered by
6
(1) kx- 2y + 6= 0
4x- 3y +9= 0
if the equations have infinately many solutions then:-
a1/a2 = b1/b2 = c1/c2
k/4 = 2/3 0r k/4= 6/9
by cross multiplication:
3k= 8 or 9k= 24
k= 8/3 or k=8/3
so, the required value of k= 8/3.
Answered by
0
Answer:8/3
Step-by-step explanation:
(1) kx- 2y + 6= 0
4x- 3y +9= 0
if the equations have infinately many solutions then:-
a1/a2 = b1/b2 = c1/c2
k/4 = 2/3 0r k/4= 6/9
by cross multiplication:
3k= 8 or 9k= 24
k= 8/3 or k=8/3
so, the required value of k= 8/3.
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