Question

Find the value of k for which each of the following systems of equations have infinitely many solutions:

I. 2x + 3y – 5 = 0

6x + ky – 15 = 0


II. kx – 2y + 6 = 0

4x – 3y + 9 = 0


III. 2x + 3y = 4

(k + 2)x + 6y = 3k + 2


IV. 2x + (k – 2)y = k

6x + (2k – 1)y = 2k + 5


V. x + (k + 1)y = 4

(k + 1) x + 9y = 5k + 2


VI. 2x – 3y = 7

(k + 2) x – (2k + 1)y = 3(2k - 1)


VII. 2x + 3y = 2

(k + 2)x + (2k + 1)y = 2(k – 1)


VIII. 2x + 3y = k

(k - 1) x + (k + 2)y = 3k


IX. kx + 3y = k – 3

12x + ky = 3


X. (k – 3)x + 3y = k

kx + ky = 12


XI. kx + 3y = 2k + 1

2(k + 1)x + 9y = 7k + 1​

Answer 1

Answer:

6 upon 15 answer hoga was question ka