Question

Find the value of k for which equation 4x^2 + 8x + k = 0 has real and
equal roots. Also find the solution of the given equation.

Pls Solve this And ill mark you brainliest Pls

Answer 1

Step-by-step explanation:

The quadratic will have real root only when its discriminant will be greater than or equal to 0

Discriminant of given equation =b

2

−4ac =(−8)

2

−4×1×k>0

⇒64−4k>0

⇒4k<64

⇒k<16

So, the value of k should be less than

Answer 2

Given equation is

$\\ \sf\longmapsto 4x^2+8x+k=0$

• a=4
• b=8
• c=k

If it has real and equal roots then The discriminant will be 0

$\\ \sf\longmapsto D=0$

$\\ \sf\longmapsto b^2-4ac=0$

$\\ \sf\longmapsto (8)^2-4(4)k=0$

$\\ \sf\longmapsto 64-16k=0$

$\\ \sf\longmapsto 64=16k$

$\\ \sf\longmapsto k=\dfrac{64}{16}$

$\\ \sf\longmapsto k=4$