Question

Find the value of k for which equation 4x^2 + 8x + k = 0 has real and equal roots. Also find the solution of the given equation. Pls Solve this And ill mark you brainliest Pls​

Answer 1

Explanation:

A quadratic equation in a variable x is an equation which is of the form ax² +bx+c = 0 where constants a, b and c are all real numbers and a ‡ 0.

Here, to find the value of k for the given quadratic equation let's compare the given equation with ax²+bx+c = 0.

After that it is given that the equation has real and equal roots, it means b² - 4ac ≤ 0 and it has real and equal roots.

Now, find the coefficient and constant of the given equation.

Comparing the given equation with the

standard form of quadratic equation, we get:

a = 4, b= 8, c k

Find the discriminate. Now it is given that the equation has real and equal roots. So,

6² - 4ac ≤ 0

(8)² - 4x4 × k ≤ 0

644 x 4 x k ≤ 0

64 - 16 x k < 0

64 -16k≤ 0

k=-64/16

k=-4

Hence, the value of k for the given quadratic equation is -4.

Hi bestu ☺

Answer 2

a=4. b=8. c=k

b^2 - 4ach

8^2 - 4*4*k

64 - 16k =0

16k = -64

k = -64/16

k = -4

real root doesnot exist

itz Mr.Pagal