Find the value of k for which equation x ^2 +5kx+16 =0 has real and equal roots
Answers
Answer:
Equation: x² + 5kx + 16 = 0
It is given that all the roots are equal.
For roots to be equal, the value of Discriminant must be equal to zero.
=> D = b² -4ac
a = 1, b = 5k, c = 16
=> D = ( 5k )² - 4 ( 1 ) ( 16 )
=> D = 25 k² - 64
We know that D is equal to zero.
=> 25k² - 64 = 0
=> 25k² = 64
=> k² = 64 / 25
=> k = √ ( 64 / 25 )
=> k = + 8 / 5 ( or ) - 8 / 5
Hope it helped !
It is given that all the roots are equal.
For roots to be equal, the value of Discriminant must be equal to zero.
=> D = b² -4ac
a = 1, b = 5k, c = 16
=> D = ( 5k )² - 4 ( 1 ) ( 16 )
=> D = 25 k² - 64
We know that D is equal to zero.
=> 25k² - 64 = 0
=> 25k² = 64
=> k² = 64 / 25
=> k = √ ( 64 / 25 )
=> k = + 8 / 5 ( or ) - 8 / 5
Hope it helped
Answer:
Step-by-step explanation:
Equation: x² + 5kx + 16 = 0
It is given that all the roots are equal.
For roots to be equal, the value of Discriminant must be equal to zero.
=> D = b² -4ac
a = 1, b = 5k, c = 16
=> D = ( 5k )² - 4 ( 1 ) ( 16 )
=> D = 25 k² - 64
We know that D is equal to zero.
=> 25k² - 64 = 0
=> 25k² = 64
=> k² = 64 / 25
=> k = √ ( 64 / 25 )
=> k = + 8 / 5 ( or ) - 8 / 5
Hope it helped ...