Question

find the value of k for which following quadratic equation have real and distinct roots: (a) kx^2+ 6x+1=0​

Answer 1

Step-by-step explanation:

• b^2-4ac =0
• a=k. b=6. c=1
• 6^2 - 4*k*1=0
• 36 - 4k= 0
• -4k = -36 (minus minus cancelled)
• 4k = 36
• k = 36/4
• k = 9