Math, asked by deepakshi78j, 1 month ago

Find the value of 'k' for which given pair of linear equations have no solution
6x + 5y = 11
3x + ky = 7​

Answers

Answered by Blazingkid
1

Step-by-step explanation:

K =4

ACC TO THE EQUATIONS IF WE TAKE DOMAIN

WE GET X AND Y AS 1 , HENCE 3(1)+K(1)=7

4+K(1)=7, K=7+1-4=8-4=4

HOPE THIS HELPS YOU

Answered by TheBrainMaster007
1

Step-by-step explanation:

Now, It is given that this equation has no solution.

we know, that

a1/a2 = b1/b2 which is not equal to c1/c2

Here, a1 = 6, b1 = 5, c1 = 11

a2 = 3, b2 = k, c2 = 7

Now, 6/3 = 5/k

6k = 15

k = 15/6

k = 5/2 ( :- divided by 3 )

Hence, the value of k is 5/2.

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