Question

find the value of (k) for which is a root of the quadratic equation kx2+x-6=0

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Answer 1

Answer:

Quadratic equation has equal roots then b

2

−4ac=0

Given that kx

2

−2kx+6=0

Here a=k,b=−2k and c=6

Now, (−2k)

2

−4×k×6=0

⇒4k

2

−24k=0

⇒4k(k−6)=0

⇒k=0 or k=6

Answer 2

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