Question

find the value of k for which is given pair of linear equation has a unique solution kx + 2 Y is equal to 3 and 2 x minus 3 Y is equal to 1​

Answer 1

Step-by-step explanation:

kx+2y=3

kx+2y=3now,

kx+2y=3now,y=3-kx/2 eq1

kx+2y=3now,y=3-kx/2 eq13x+6y=10

kx+2y=3now,y=3-kx/2 eq13x+6y=10y=10-3x/6 eq2

kx+2y=3now,y=3-kx/2 eq13x+6y=10y=10-3x/6 eq2now put these eqs equal.

kx+2y=3now,y=3-kx/2 eq13x+6y=10y=10-3x/6 eq2now put these eqs equal.3-kx/2 = 10-3x/6

kx+2y=3now,y=3-kx/2 eq13x+6y=10y=10-3x/6 eq2now put these eqs equal.3-kx/2 = 10-3x/6now cross multiplication.

kx+2y=3now,y=3-kx/2 eq13x+6y=10y=10-3x/6 eq2now put these eqs equal.3-kx/2 = 10-3x/6now cross multiplication.6(3-kx) = 2(10-3x)

kx+2y=3now,y=3-kx/2 eq13x+6y=10y=10-3x/6 eq2now put these eqs equal.3-kx/2 = 10-3x/6now cross multiplication.6(3-kx) = 2(10-3x)18 - 6kx = 20 - 6x

kx+2y=3now,y=3-kx/2 eq13x+6y=10y=10-3x/6 eq2now put these eqs equal.3-kx/2 = 10-3x/6now cross multiplication.6(3-kx) = 2(10-3x)18 - 6kx = 20 - 6x18 - 6k = 20 - 6

kx+2y=3now,y=3-kx/2 eq13x+6y=10y=10-3x/6 eq2now put these eqs equal.3-kx/2 = 10-3x/6now cross multiplication.6(3-kx) = 2(10-3x)18 - 6kx = 20 - 6x18 - 6k = 20 - 618 - 6k = 14

kx+2y=3now,y=3-kx/2 eq13x+6y=10y=10-3x/6 eq2now put these eqs equal.3-kx/2 = 10-3x/6now cross multiplication.6(3-kx) = 2(10-3x)18 - 6kx = 20 - 6x18 - 6k = 20 - 618 - 6k = 1418 - 14 = 6k

kx+2y=3now,y=3-kx/2 eq13x+6y=10y=10-3x/6 eq2now put these eqs equal.3-kx/2 = 10-3x/6now cross multiplication.6(3-kx) = 2(10-3x)18 - 6kx = 20 - 6x18 - 6k = 20 - 618 - 6k = 1418 - 14 = 6k4/6 = k

kx+2y=3now,y=3-kx/2 eq13x+6y=10y=10-3x/6 eq2now put these eqs equal.3-kx/2 = 10-3x/6now cross multiplication.6(3-kx) = 2(10-3x)18 - 6kx = 20 - 6x18 - 6k = 20 - 618 - 6k = 1418 - 14 = 6k4/6 = k2/3 = k

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Answer 2

I hope it's helpful for you...

Mark Brainlist Answer :-)

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